Ruling Pulling a Lv.X
- Thread starter Mudkip711
- Start date
1. Have a very accurate natural way of weighing objects.
2. Use a digital scale.
2. Use a digital scale.
A digital scale going out to as many decimals as possible (preferably at least .000). Holofoil cards weigh slightly more than normal cards, so the heavier the pack, the better, right?
Umm, ask where they are going to hand out first and sit aproximitely (sorry Bad Spelling) about where they would hand out the place where the LV.X is, PM me if you pull a LV.X by my help or what you pulled.
1) Sneak into the TCG factory.
2) Hack the booster box-packing "random" algorithm (no, there doesn't exist real randomness in this world, as far as machines go anyway).
3) Change it so it's always a number you can remember.
4) Profit. Just don't tell your friends about it.
2) Hack the booster box-packing "random" algorithm (no, there doesn't exist real randomness in this world, as far as machines go anyway).
3) Change it so it's always a number you can remember.
4) Profit. Just don't tell your friends about it.
^Has exactly nothing to do with it. The number and type of cards we get is obviously determined before packing.
However, back on topic, whether there will be a LV. X in the pack or not, there is a certain chance involved. A machine, some kind of simple computer I suppose, will throw this chance (which seems to be about 1/72 in the current sets? Maybe a bit higher) into a formula, the algorithm, to see which packs actually get the LV. X and which don't. The formula, of course, is not random at all, in fact I think it's fixed (since a randomizer randomizing the formula would be strange, since this would eventually lead to an infinite loop where you still don't have 100% randomness. Also, doing this is a bit paranoid, since the issue isn't really life-threatening or something, and a slightly higher number of Lv. X won't affect anyone).
However, back on topic, whether there will be a LV. X in the pack or not, there is a certain chance involved. A machine, some kind of simple computer I suppose, will throw this chance (which seems to be about 1/72 in the current sets? Maybe a bit higher) into a formula, the algorithm, to see which packs actually get the LV. X and which don't. The formula, of course, is not random at all, in fact I think it's fixed (since a randomizer randomizing the formula would be strange, since this would eventually lead to an infinite loop where you still don't have 100% randomness. Also, doing this is a bit paranoid, since the issue isn't really life-threatening or something, and a slightly higher number of Lv. X won't affect anyone).
go to four different stores and by 1 booster each my friend did that and got 4 lvxs!
The only thing I know about the puuling of a LV.X is that there is always at least one in a box unless there is a packaging error. (found due to mathematical odds)