Finished Prof. Slowking's Haven for Complications and Computations of Equation Calculations! [YPPY]

[Keeper of Night]

4x(9-9)=9-9

3 4 3 7 7

 

[bbninjas]

(3-3)*4 = 7-7

38922

 

[simsands]

(9+3)/2=8-2

Count: 24

7 1 2 0 5

 

[Celever]

7x1=2+5+0

Count: 7

53129

 

[Vracken]

5-2*1=9/3

85291

 

[Keeper of Night]

8/2+5=9x1

4 4 6 9 1

 

[bbninjas]

4/4 = 6*9*1

23378

 

[Vracken]

8-2^(3-3)=7

41263

 

[Celever]

2x6=4x3x1

Count: 8

31948

 

[thegrovylekid]

3+1=9/4x8

59874

 

[Keeper of Night]

(8-7)x4+5=9

3 4 1 9 1

 

[simsands]

9-3=4+1+1

0 9 5 9 4

 

[Celever]

5+4x0=9-9

Count: 9

41558

 

[thegrovylekid]

4 - 5 (5/8) + 1

4 5 9 0 7

count: 2

 

[simsands]

5-4=(9*7)^0

44973

 

[Celever]

(4/4)+9=7+3

Count: 10

52581

 

[Robin Aisaga]

5+5=(2x1)+8

Count: 10

23899

 

[thegrovylekid]

9x9 + 3/2 - 8

99999

 

[Robin Aisaga]

@thegrovylekid
I'm not sure how to explain this, I'm not a math teacher. But you have to create a complete equation using the five random digits. So including the outcome. You always have to use the = symbol. The original post explains this very well. It also includes some examples.

 

[Vracken]

9(9-9)=9-9

14827