Help Swiss style: deciding winner with same record??

Jaypenny777

Jaypenny777

Aspiring Trainer
Member
So I have a question that maybe you the pokebeach community can resolve for me. Yesterday I attended a league challenge at my local event. The format was expanded and it was a 3 round swiss tournament. My first two matches I went 2-0 against both opponents. The third and final deciding round I won the first match and my opponent took the second match. Time was then called as we were setting up the third match. The organizer called our game a draw. My opponent had won his first round 2-0 and his second round 2-1. I believe I should have won the tournament because I had zero losses the entire tournament but he had one. When it came to announce the winner my opponent won because we had the same opponent winner percentage but he had a 1% better opponent's opponents winner percentage. Does this sound correct how the winner was chosen? Thank you guys for your input.
 
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That is correct that is the official tournament rules for tie breakers, and that is how it’s done in all other tcg tournaments as well.

Using round record would be pretty arbitrary since it doesn’t accurately indicate the quality of the match or player. 2-0 could mean that you are so skilled you played perfectly and beat your opponent handily. Or is could mean your opponent was so bad they couldn’t play there way out of a paper bag so you’d be 2-0 regardless of skill. 2-1 could mean you made some mistakes in the second game but pulled through. Or 2-1 could mean you played against an awful match up for your deck but played so skillfully you snatched victory against all odds.

Opponent W/L record is just a more accurate approach when looking for breaking ties. If Im x-0 and beat a bunch of x-1 players and you’re x-0 but only beat players who were x-4, clrealy I had to execute higher skilled play then you did.
 
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